|
Name: Brooksville Seventh-Day Adventist Church Class: House of Worship Location: Hernando County, Florida, United States of America U.S. Board on Geographic Names ID: 2104909 Brooksville Seventh-Day Adventist Church is located at: Latitude: 28.5525° North (28°33’09” North) Longitude: 82.4077778° West (82°24’28” West) Elevation: 29 meters above sea level. Source: U.S. Board on Geographic Names, as of 1 November 2020. If this name is incorrect or outdated, help them update their data: U.S. Board on Geographic Names (Or the institution may write to them on official letterhead.) |