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Name: Seventh Day Adventist Church of Sanford Class: House of Worship Location: Seminole County, Florida, United States of America U.S. Board on Geographic Names ID: 299932 Seventh Day Adventist Church of Sanford is located at: Latitude: 28.805826° North (28°48’21” North) Longitude: 81.2720091° West (81°16’19” West) Elevation: 8 meters above sea level. Source: U.S. Board on Geographic Names, as of 1 November 2020. If this name is incorrect or outdated, help them update their data: U.S. Board on Geographic Names (Or the institution may write to them on official letterhead.) |