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Name: Tekakwitha Friary Class: House of Worship Location: Montgomery County, New York, United States of America U.S. Board on Geographic Names ID: 967124 Tekakwitha Friary is located at: Latitude: 42.9495179° North (42°56’58” North) Longitude: 74.3929134° West (74°23’34” West) Elevation: 91 meters above sea level. Source: U.S. Board on Geographic Names, as of 1 November 2020. If this name is incorrect or outdated, help them update their data: U.S. Board on Geographic Names (Or the institution may write to them on official letterhead.) |