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Name: Oakley Church of Christ Class: House of Worship Location: Hamilton County, Ohio, United States of America U.S. Board on Geographic Names ID: 1062298 Oakley Church of Christ is located at: Latitude: 39.1531151° North (39°09’11” North) Longitude: 84.4335523° West (84°26’01” West) Elevation: 188 meters above sea level. Source: U.S. Board on Geographic Names, as of 1 November 2020. If this name is incorrect or outdated, help them update their data: U.S. Board on Geographic Names (Or the institution may write to them on official letterhead.) |