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Name: Seybert Church Class: House of Worship Location: Sandusky County, Ohio, United States of America U.S. Board on Geographic Names ID: 1068221 Seybert Church is located at: Latitude: 41.2761647° North (41°16’34” North) Longitude: 82.8482431° West (82°50’54” West) Elevation: 232 meters above sea level. Source: U.S. Board on Geographic Names, as of 1 November 2020. If this name is incorrect or outdated, help them update their data: U.S. Board on Geographic Names (Or the institution may write to them on official letterhead.) |